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Di erentiating and dividing by L yields d 2 i R di 1 i 0 2 L dt LC dt A solution of this second-order di erential equation is of the form i A1 es1 t A2 es2 t . solution in the di erential equation obtains Substituting this

2.8 Applying postulates to statements Complete each sentence and state the postulate that applies. (a) If Harry and Alice are the same age today, then in 10 years _____ .

Fig. 8-3

Fig. 9-25

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(b) Since 32 F and 0 C both name the temperature at which water freezes, we know that _____ . (c) If Henry and John are the same weight now and each loses 20 lb, then _____ .

R 1 R 1 A1 es1 t s2 s1 A2 es2 t s2 s2 0 1 2 L LC L LC that is, if s1 and s2 are the roots of s2 R=L s 1=LC 0, R s1 2L where R=2L, s 2 R 1 2L LC R s2 2L s 2 R 1 2L LC

Since the input current to the op amp is negligible, iR % iD Io evD = VT But since the inverting terminal is a virtual ground, vD vi . Thus, vo iR R % RIo evi = VT RIo ln 1 vi VT

CHAP. 8]

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(d) If two stocks of equal value both triple in value, then _____ . (e) If two ribbons of equal size are cut into five equal parts, then _____ . (f) If Joan and Agnes are the same height as Anne, then _____ . (g) If two air conditioners of the same price are each discounted 10 percent, then _____ .

Having now at your disposal a logarithmic ampli er (Example 9.8 and Problem 9.17) and an exponential (inverse log) ampli er (Problem 9.18), devise a circuit that will multiply two numbers together.

Overdamped Case > !0 In this case, both and are real positive numbers. i A1 e t A2 e t e t A1 e t A2 e t

(a) They will be the same age. (Add. Post.) (b) 32 F 0 C. (Trans. Post.)

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, L 0:10 H, and C 13:33 mF, has an initial charge on the capacitor of Q0 2:67 10 3 C. A switch is closed at t 0, allowing the capacitor to discharge. Obtain the current transient. (See Fig. 8-4.) For this circuit, q R 1 103 s 1 ; 7:5 105 s 2 ; !2 and 2 !2 500 s 1 0 0 2L LC Then, i e 1000t A1 e500t A2 e 500t

(c) They will be the same weight. (Subt. Post.) (d) They will have the same value. (Mult. Post.) (e) Their parts will be of the same size. (Div. Post.) (f) Joan and Agnes are of the same height. (Trans. Post.) (g) They will have the same price. (Subt. Post.)

CHAP. 9]

The values of the constants A1 and A2 are obtained from the initial conditions. The inductance requires that i 0 i 0 . Also the charge and voltage on the capacitor at t 0 must be the same as at t 0 , and vC 0 Q0 =C 200 V. Applying these two conditions, 0 A1 A2 and 2000 500A1 1500A2

Applying geometric postulates State the postulate needed to correct each diagram and accompanying statement in Fig. 2-20.

Lo _

If the negative value is taken for A1 , the function has simply ipped downward but it has the same shape. The signs of A1 and A2 are xed by the polarity of the initial voltage on the capacitor and its relationship to the assumed positive direction for the current.

Fig. 2-20

Fig. 8-4

Fig. 7-30

(a) Postulate 17. (b) Postulate 18. (c) Postulate 14. (d) Postulate 13. (AC is less than the sum of AB and BC.)

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